it will print "0" i.e zero since compiler wont get to the print

fun(int x)
{
if(x > 0)
fun(x/2);
printf("%d", x);
}

above function is called as:
fun(10);

what will it print?

}

Question Posted / mortal

Answer Posted / mortal

it will print "0" i.e zero since compiler wont get to the
print statement until the value is zero.

Is This Answer Correct ?

2 Yes

5 No

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