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The length of the base of a triangle is three times the
height. The area of the triangle is 24 square inches.
Find the length of the base of the triangle. (Area=1/2bh)
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Answer / kaneez-e-zainab
Area of triangle = 1/2 bh
b=3 times of height, i.e., 3h
h=?
b=3h
A= 24
A=1/2bh
24=1/2*3h*h
48=1*3h2 (when bases are same power should be added)
(poweris 2)
48=3h to the power of 2
h2=16
Square root of h=4
b=3*h=3*4=12
b=12
prof
A=1/2bh
A=1/2*12*4
A=6*4
A=24
| Is This Answer Correct ? | 6 Yes | 3 No |
Answer / supriya khedkar
a=1/2b*h
b=3*h
a=24
so 1st we find out
a=1/2*3*h2 (h2=h square)
24=1/2*3*h2
24*2=3*h2
48/3=h2
16=h2
so h=4
but we want length b
and b=3*4=12
so ans is 12
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / ritesh kunte
see here,
if we consider height as h, and lenght as l
then
given height= 3* lengh
Area of triangle = 1/2*h*l;
if we consider lengh = x, then
heigh = 3x
so 24=1/2* X * 3X;
3X(sqaure)= 48;
so X(squr) = 48/3;
i.e X=4;
so lenght = 4;
and height = 3 * 4 = 12 ;
| Is This Answer Correct ? | 2 Yes | 4 No |
Answer / nandha kumar
base=3(height)
area=1\2*b*h
=> area = 1\2*3*h^2
24^2=3\2*h^2
taking sq.root on both sides
24=[(3\2)^1\2]*h
24*[(2\3)^1\2]=h
h=19.56 1nch
hence b=3*h
=>b=3*19.56
b=58.78 inch
| Is This Answer Correct ? | 4 Yes | 17 No |
Answer / anusha
Given:
area=24, and base of triangle= height of the triangle
therfor, b=h
a=1/2b^2 => 24=1/2(b)^2.
b^2= 48 => b=6.92
| Is This Answer Correct ? | 33 Yes | 67 No |
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