Answer / suresh

Base class constructor called first next it wil call Derived
class constructor

Answer / sangeetha

"C++ classes honor their parents by calling their parents
constructor before they call their own." The base class
constructor will be called before the derived class
constructor. This makes sense because it guarantees that
the base class is properly constructed when the constructor
for the derived class is executed. This allows you to use
some of the data from the base class during construction of
the derived class.

Answer / prajeesh

#include <iostream>
using namespace std;

class BaseClass {
public:
BaseClass() { cout << "Constructing base portion\n"; }
~BaseClass() { cout << "Destructing base portion\n"; }
};

class DerivedClass: public BaseClass {
public:
DerivedClass() { cout << "Constructing derived
portion\n"; }
~DerivedClass() { cout << "Destructing derived
portion\n"; }
};

int main()
{
DerivedClass ob;

// do nothing but construct and destruct ob

return 0;
}
Constructing base portion
Constructing derived
Destructing derived
Destructing base portion

Answer / nathusingh

If both the base and derived class have constructors then
first of all constructor of the Base Class (Parent class)
will be invoked and then subsequently the constructor of
the derived class will be called.Whereas in case of
Destructors,destructor of the derived is called so as to
destroy the object child object and then base class
destructor is called. In Case of Creation ( constructors)
Parents(Base Class) are honored first while in case of
destruction (destrcutors) children( Derived class) are made
the victim :)

Answer / ctharam

1) First of all, Base class constructor called and then Derived class constructor will call.

Answer / harsha

First Constructor of base class will be invoked and then the
constructor of derived will be invoked ........

For example
Using System;
class Base
{
public Base()
{
Console.WriteLine("Base Class");
}
}
class Derived:Base
{
public Derived()
{
Console.WriteLine("Derived Class");
}
static void Main(string[] args)
{
Derived d=new Derived();
}
}

Output:
Base Class
Derived Class

Answer / nageswararao

Both Base and Derived class constructor Get invoked when
both base and derived has constructors and and we create an
object for derive class?

Answer / sachin moule

Base class constructor is get called first and later on
derived same will happen in case of destructor

Answer / amrit kumar singh

#include <iostream>
using namespace std;

class BaseClass {
public:
BaseClass() { cout << "Constructing base portion\n"; }
~BaseClass() { cout << "Destructing base portion\n"; }
};

class DerivedClass: public BaseClass {
public:
DerivedClass() { cout << "Constructing derived portion\n"; }
~DerivedClass() { cout << "Destructing derived portion\n"; }
};

int main()
{
DerivedClass ob;

// do nothing but construct and destruct ob

return 0;
}

output will be :-----------
Constructing base portion
Constructing derived
Destructing base portion
Destructing derived

Answer / dipa

It will show compilation error that "class type
redefination".

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