Answer / vignesh1988i

#include<stdio.h>
#include<conio.h>
void main()
{
char a[100],n;
int count=0;
printf("enter the string");
gets(a);
printf("enter the letter to be searched");
scanf("%c",&n);
for(int i=0;a[i]!='\0';i++)
{
if(a[i]==n)
{
count++;
}
}
printf("so the number of occurances of the given %c
is ",count);
getch();
}

Answer / sankara subramanian.n

#include<stdio.h>
#include<conio.h>
void main()
{
char a[100];
int i,count=1;
clrscr();
printf("Enter the string:");
gets(a);
for(i=0;a[i]!='\0';i++)
{
count++;
}
getch();
}

write a program to Insert in a sorted list

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main(){ char a[100]; a[0]='a';a[1]]='b';a[2]='c';a[4]='d'; abc(a); } abc(char a[]){ a++; printf("%c",*a); a++; printf("%c",*a); }

2 Answers  

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void func1(int (*a)[10]) { printf("Ok it works"); } void func2(int a[][10]) { printf("Will this work?"); } main() { int a[10][10]; func1(a); func2(a); } a. Ok it works b. Will this work? c. Ok it worksWill this work? d. None of the above

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Given an array of characters which form a sentence of words, give an efficient algorithm to reverse the order of the words (not characters) in it.

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