In 1000 wine bottles stack 10 are poisoned given 10 rats
what is the minimum number of tries to find the poisoned
one. Rat dies once it licks the poisoned wine.
Answers were Sorted based on User's Feedback
Answer / vahid
Answer: 10
Reason:
The best case happens ONLY when each rat dies just as they
taste the FIRST bottle given to them (you can imagine it a
miracle :D )
In this case, the very first 10 attempts reveal the
poisonous bottles. So the answer is 10.
Is This Answer Correct ? | 23 Yes | 13 No |
Answer / harsh
10 number of tries ........
number the bottles in the binary format (0,1)
Is This Answer Correct ? | 15 Yes | 14 No |
Answer / somesh bansal
Answer is 999. since it is a stack of bottles...last bottle(lowest in the stack) can be a poisonous one...poisoned bottles are randomly placed in stack...so in order to access last bottle rats have to go through all 999 bottles above it...
Is This Answer Correct ? | 3 Yes | 4 No |
Answer / manoj kumar paikray
7 tries. as 1000=8 and 10=2 (binary code).
Is This Answer Correct ? | 1 Yes | 8 No |
Answer / lime
1000 bottles
10 poison bottles
10 rats
one out of every 100 bottles is poisoned
each rat licks a bottle
probability is that the 100th lick will find a poison bottle
Is This Answer Correct ? | 3 Yes | 12 No |
Answer / saurabh
1
Probably 1st bottel may be full wid poison...!!
Is This Answer Correct ? | 4 Yes | 16 No |
Answer / karuppasamy
0[because one rat is known, others aren't tried
Is This Answer Correct ? | 4 Yes | 17 No |
Answer / abhisek dash
since it is a probability type question
so according to me the answer would be
10/1000=.001 times
Is This Answer Correct ? | 2 Yes | 20 No |
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