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In 1000 wine bottles stack 10 are poisoned given 10 rats
what is the minimum number of tries to find the poisoned
one. Rat dies once it licks the poisoned wine.
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Answer / vahid
Answer: 10
Reason:
The best case happens ONLY when each rat dies just as they
taste the FIRST bottle given to them (you can imagine it a
miracle :D )
In this case, the very first 10 attempts reveal the
poisonous bottles. So the answer is 10.
| Is This Answer Correct ? | 23 Yes | 13 No |
Answer / harsh
10 number of tries ........
number the bottles in the binary format (0,1)
| Is This Answer Correct ? | 15 Yes | 14 No |
Answer / somesh bansal
Answer is 999. since it is a stack of bottles...last bottle(lowest in the stack) can be a poisonous one...poisoned bottles are randomly placed in stack...so in order to access last bottle rats have to go through all 999 bottles above it...
| Is This Answer Correct ? | 3 Yes | 4 No |
Answer / maduhansa
Answer is 1 . One tries to find a poisonous one
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / manoj kumar paikray
7 tries. as 1000=8 and 10=2 (binary code).
| Is This Answer Correct ? | 1 Yes | 8 No |
Answer / lime
1000 bottles
10 poison bottles
10 rats
one out of every 100 bottles is poisoned
each rat licks a bottle
probability is that the 100th lick will find a poison bottle
| Is This Answer Correct ? | 3 Yes | 12 No |
Answer / saurabh
1
Probably 1st bottel may be full wid poison...!!
| Is This Answer Correct ? | 4 Yes | 16 No |
Answer / karuppasamy
0[because one rat is known, others aren't tried
| Is This Answer Correct ? | 4 Yes | 17 No |
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