What is the number of zeros of the product of the first 100
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Answer / sooraj
|Is This Answer Correct ?||36 Yes||5 No|
Answer / cnu
exp: 0 is formed by multiplying 5 with 2. so first we find
how many 5's and 2's are there in 100!.
No of 5's : 100/5=20/5=4/5.
20 +4 =24.
No of 2's : 100/2=50/2=25/2=12/2=6/2=3/2=1/2.
50 +25 +12 +6 +3 +1.
It has 24 5's and 2's.
so the no. of zeros=24.
|Is This Answer Correct ?||24 Yes||0 No|
Answer / mohammed ghouse
|Is This Answer Correct ?||24 Yes||4 No|
Answer / sumit
It will be minimum of power of 2 and 5 as product of 2 and 5
Power of 2 in this case 94
Power of 5 in this case 24
So answer is 24
|Is This Answer Correct ?||14 Yes||0 No|
Answer / daya
the product of (even number) and 5 results in "0" of unit's
no. of 5's from 1 to 100 = 100/5 = 20
but in 25, 50, 75 and 100, there is one more 5
25 = 5*5*1
50 = 5*5*2
75 = 5*5*3
four 5's extra
therefore no. 0f F's = 20+4 = 24
|Is This Answer Correct ?||8 Yes||1 No|
Answer / rashmi
The product of the first 100 numbers is
so the number of zeros of the product of the first 100
numbers is 143.
|Is This Answer Correct ?||5 Yes||0 No|
Answer / praveen
if it is 0*1*2........*100 clearly answer is 1;if 4m
1*2*....100 answer is 24
|Is This Answer Correct ?||9 Yes||5 No|
Answer / deepak
Any Number N you want to find the number of zeros in
product expand it in Standard form say for example
No of 2's= 3
No of 5's= 3 as 2*5=10 so there are 3 combinations of 2*5
so totaly 3 zeros.
For Fafctorial just use this 100! = [100/5]+[100/25]=20+4=24
|Is This Answer Correct ?||4 Yes||0 No|
Answer / kishor
|Is This Answer Correct ?||2 Yes||0 No|
Answer / davinder
100! = 93,326,215,443,944,102,188,325,606,108,575,267,240,944,254,854,960,571,509,166,910,400,407,995,064,242,937,148,632,694,030,450,512,898,042,989,296,944,474,898,258,737,204,311,236,641,477,561,877,016,501,813,248
|Is This Answer Correct ?||1 Yes||0 No|
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