Answer Posted / rohit parimal

a+b+c=13 - eq 1

c+d+e=13 - eq 2

e+f+g=13 - eq 3

g+h+i=13 - eq 4

we will add all the equations

a+b+c+c+d+e+e+f+g+g+h+i=52 - eq 5

a+b+c+d+e+f+g+h+i+(c+e+g)=52

as the numbers are from 1 to 9
the addition of nine numners from 1 to 9 is 45.
so
a+b+c+d+e+f+g+h+i=45 -eq 6

Putting the value from eq 6 in eq 5

45+c+e+g=52 - eq 7

c+e+g=7 - eq 8

eq 2 says c+d+e=13

Subtracting eq 8 from eq 2

c+d+e-c-e-g=13-7

d-g=6 - eq 9

when we put value 4 in g then the value of d should be 10.
Objction.
So value of g is 1 or 2.

eq 3 says e+f+g=13

When we put the vaue of g as 1 then f should be 8 and e
should be 4.
When we put the value of g as 2 then f should be 9 and e
should be 2.Objection (because no two alphabets can be
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