Answer Posted / anjum kabir

A + B + C | 9 + 3 + 1 = 13 = 6 + 5 + 2
C + D + E | 1 + 8 + 4 = 13 = 2 + 7 + 4
E + F + G | 4 + 7 + 2 = 13 = 4 + 8 + 1
G + H + I | 2 + 5 + 6 = 13 = 1 + 3 + 9
Value of E = 4

13*4 = 52
1+2+3+....+9 = 45

Then C+D+E must be equal to 7
or they must from 1 , 2 or 4.

1 and 2 for E cannot satisfy as because 1 and 2 cannot
come together in C+D+E
hence 1 and 4 and 2 and 4 should be together.

so you get two solutions and putting them any of the either
way you get E = 4. and everynumber gets satisfied with a
unique value.

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