Answer / tanish

Use an array
int [] funct1();

Answer / krishna

You will have to use a structure or an array and then return
a pointer to the structure/array.

How to use power function under linux environment.eg : for(i=1;i<=n;i++){ pow(-1,i-1)} since it alerts undefined reference to 'pow'.

2 Answers  

---

posted by surbhi just now main() { float a = 5.375; char *p; int i; p=(char*)&a; for(i=0;i<=3;i++) printf("%02x",(unsigned char) p[i]); } how is the output of this program is :: 0000ac40 please let me know y this output has come

2 Answers   GATE,

---

What is the problem with the following code segment? while ((fgets(receiving array,50,file_ptr)) != EOF) ;

1 Answers  

---

union u { union u { int i; int j; }a[10]; int b[10]; }u; main() { printf("\n%d", sizeof(u)); printf(" %d", sizeof(u.a)); // printf("%d", sizeof(u.a[4].i)); } a. 4, 4, 4 b. 40, 4, 4 c. 1, 100, 1 d. 40 400 4

3 Answers   HCL,

---

write a c program to Create a registration form application by taking the details like username, address, phone number, email along with password and confirm password (should be same as password).Ensure that the password is of 8 characters with only numbers and alphabets. Take such details for 5 users and display the details. In place of password display “****”. (Use Structures).

0 Answers   CDAC, College School Exams Tests,

---

---

Is the following code legal? typedef struct a aType; struct a { int x; aType *b; };

1 Answers  

---

Design an implement of the inputs functions for event mode

0 Answers   Wipro,

---

main() { unsigned char i=0; for(;i>=0;i++) ; printf("%d\n",i); }

1 Answers  

---

what is variable length argument list?

2 Answers  

---

main() { int c[ ]={2.8,3.4,4,6.7,5}; int j,*p=c,*q=c; for(j=0;j<5;j++) { printf(" %d ",*c); ++q; } for(j=0;j<5;j++){ printf(" %d ",*p); ++p; } }

2 Answers   CSS, Wipro,

---

How to palindrom string in c language?

6 Answers   Google,

---

main() { static int a[3][3]={1,2,3,4,5,6,7,8,9}; int i,j; static *p[]={a,a+1,a+2}; for(i=0;i<3;i++) { for(j=0;j<3;j++) printf("%d\t%d\t%d\t%d\n",*(*(p+i)+j), *(*(j+p)+i),*(*(i+p)+j),*(*(p+j)+i)); } }

1 Answers  

---