the solution of the system of equations 2y-z=0,x+3y=-4,3x+4y=3 is
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Answer / Ajit Tiwari
We can solve this system by eliminating one variable. Adding the third equation to twice the second equation, we get 5y = 4. Solving for y, we find y = 4/5. Substituting y = 4/5 in the first equation, we find z = 2(4/5) = 8/5. Now, substituting y = 4/5 and z = 8/5 in the second equation, we find x = -3 * (4/5) - y = -17/5. So, the solution of the system is x = -17/5, y = 4/5, z = 8/5.
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