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VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – QUESTION 9 : In a shift-code, the letters of the alphabet are replaced by the numbers 1 to 26 starting at some letters. An example is : A = 25, B = 26, C = 1, D = 2, E = 3, F = 4, G = 5, H = 6, I = 7, J = 8, K = 9, L = 10, M = 11, N = 12, O = 13, P = 14, Q = 15, R = 16, S = 17, T = 18, U = 19,V = 20, W = 21, X = 22, Y = 23, Z = 24. There are two shift-codes in which the sum of the numbers representing the letters of the word HOLE is 48. What is the sum of the numbers representing the letters of the word BLACK in each of these codes?
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VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – ANSWER 9 : 39, 78. By first trial calculation, H + O + L + E = 10 + 17 + 14 + 7 = 48, B + L + A + C + K = 4 + 14 + 3 + 5 + 13 = 39. By second trial calculation, H + O + L + E = 23 + 4 + 1 + 20 = 48, B + L + A + C + K = 17 + 1 + 16 + 18 + 26 = 78.
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