Answer / mithun shrivastav

#include<stdio.h>

void main()
{
int n,sum = 0,rev = 0;
print("\nEnter an Integer No. : ");
scanf("%d", &n);

while(n>0)
{
sum = sum * 10 + n%8;
n = n/8;
}

while(sum > 0)
{
rev = rev*10 + sum%10;
sum = sum/10;
}

printf("Octal Equivalent = ", rev);

getch();
}

Answer / nitin sokhal

This program is Correct

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0 Answers  

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void ( * abc( int, void ( *def) () ) ) ();

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why nlogn is the lower limit of any sort algorithm?

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