char *someFun()
{
char *temp = “string constant";
return temp;
}
int main()
{
puts(someFun());
}
Answer / susie
Answer :
string constant
Explanation:
The program suffers no problem and gives the output
correctly because the character constants are stored in
code/data area and not allocated in stack, so this doesn’t
lead to dangling pointers.
| Is This Answer Correct ? | 4 Yes | 0 No |
main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); } int i;
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