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print a semicolon using Cprogram without using a semicolon
any where in the C code in ur program!!
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Answer / arunabha
#include<stdio.h>
#include<conio.h>
void main()
{
if(printf("%c",59)){}
if(getch()){}
}
this is the perfect solution...
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / rahul
void main()
{
if(printf("%c",59))
{}
if(getch())
}
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / poorna
#include<stdio.h>
void main()
{
if(printf("\n welcome \n"))
}
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / neeraj gupta
#include<stdio.h>
void main()
{
printf("%c",59);
}
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / abinash
void main()
{
if(printf("semicolon")){}
}
this works,if u include (stdio.h)
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / gaurav sharma
void main()
{
if(printf("%c",59))
{}
if(getch())
}
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / sam prasanna
we can use the ASCII value of semicolon(;) to print it in if condition.
| Is This Answer Correct ? | 0 Yes | 0 No |
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C Code 
