Answer / arunabha

#include<stdio.h>
#include<conio.h>
void main()
{
if(printf("%c",59)){}
if(getch()){}
}
this is the perfect solution...

Answer / shan

printf("use of semicolon is like this\;\n");

Answer / rahul

void main()
{
if(printf("%c",59))
{}
if(getch())
}

Answer / yacub

main()
{
if(printf("%c",59))
{}
}

Answer / poorna

#include<stdio.h>
void main()
{
if(printf("\n welcome \n"))
}

Answer / neeraj gupta

#include<stdio.h>
void main()
{
printf("%c",59);
}

Answer / abinash

void main()
{
if(printf("semicolon")){}
}

this works,if u include (stdio.h)

Answer / gaurav sharma

void main()
{
if(printf("%c",59))
{}
if(getch())
}

Answer / krish

main()
{
printf(".");
printf("\n,");
}

Answer / sam prasanna

we can use the ASCII value of semicolon(;) to print it in if condition.

main() { int i=-1; +i; printf("i = %d, +i = %d \n",i,+i); }

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