Answer / nipun

#include<stdio.h>
#include<conio.h>

void main()
{
int var;
int count=0;
int n=0;
clrscr();
while(n<10)
{
printf("Enter the number:");
scanf("%d",&var);
if(var%2 == 0)
{
count++;
n++;
}
else
{
n++;
continue;
}
}
printf("Even numbers present:%d",count);
getch();
}

Answer / sansiri

#include<stdio.h>
#include<conio.h>
void main()
{
int n,i=0;
int count=0;
printf("\n Enter the 10 integer numbers");
while(i<10)
{
scanf("%d",&n);
if(n%2==0)
{
count++;
}
i++;
}
printf("\nCount of even numbers:%d",count);
getch();
}

printf

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errors are known as?

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printy(a=3,a=2)

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