WHAT WILL BE THE OUTPUT OF THE FOLLOWING QUESTION
void main()
{
int x=4,y=3,z;
z=x-- -y;
printf("%d%d%d",x,y,z);
}
Answers were Sorted based on User's Feedback
Answer / shreyas
the answer is 3 3 1..........
while computing value of z ....x will be 4 .....but while
printing its value it has been decremented by 1 and hence x=3.
| Is This Answer Correct ? | 42 Yes | 2 No |
Absolutely.. 3 3 1
No doubt in it.....all frnds who said it are right and their
explaination is also correct......
while Z is calculated X is 4...since it is post decrement....
| Is This Answer Correct ? | 12 Yes | 3 No |
Answer / amrita mohanty
3,3,1
since it is a post increment operation,so x--=4 initially.
but after that the value of x becomes 3.
x-- - y = 4-3=1
therefore x=3,y=3,z=1
| Is This Answer Correct ? | 9 Yes | 0 No |
Answer / anjana priyadharshini
THE OUTPUT IS: 3,3,1
THE PEOPLE WHO TOLD THIS ANSWER THEIR EXPLANATION IS CORRECT
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / medo
#include<stdio.h>
void main()
{ int x,y,z;
{
int x=4,y=3,z;
z=x---y;
printf("x=%d\ny=%d\nz=%d\n",x,y,z);
}
}
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / vishnu
initally x=4,y=3
z=x-- -y;
after doing x-y operation and that value wil be assigned to
z.there followed by x value wil be decreased by 1.
hence z=4-3 z=1
x=4-1 x=3
y=3
hence output will be
3,3,1
| Is This Answer Correct ? | 2 Yes | 0 No |
quoroum of computer languages?
How to develop a program using C language to convert 8-bit binary values to decimals. TQ
#include<>stdio.h> #include<>conio.h> { printf("hello"); void main() getch(); } what the out put of this program and why ......plz clear my answer
I am using Qt 5.6 during compilation it stops and gives error about Qmake The process "C:QtQt5.6.35.6.3msvc2015_64inqmake.exe" crashed. Error while building/deploying project untitled1 (kit: Desktop Qt 5.6.3 MSVC2015 64bit) When executing step "qmake"
#include<iostream.h> #include<stdlib.h> static int n=0; class account { int age,accno; float amt; char name[20]; public: friend void accinfo(account [] ,int); void create(); void balenq(); void deposite(); void withdrawal(); void transaction(account []); }; void account :: create() { static int acc=1231; accno=acc+n; cout<<"\n\tENTER THE CUSTOMER NAME : "; cin>>name; cout<<"\n\t ENTER THE AGE : "; cin>>age; cout<<"\n\t ENTER THE AMOUNT : "; cin>>amt; // if(amt<=500) // cout<<"\n\tAMOUNT IS NOT SUFFICIENT TO CREATE AN ACCOUNT..."; cout<<"\n\t YOUR ACCOUNT NUMBER : "<<accno<<endl; n++; } void accinfo(account cus[],int ch) { int no,flag=0; cout<<"\n\t\tENTER YOUR ACCOUNT NUMBER : "; cin>>no; for(int i=0;i<=n&&flag==0;i++) if(no==cus[i].accno) { flag=1; switch(ch) { case 2: cus[i].balenq(); break; case 3: cus[i].deposite(); break; case 4: cus[i].withdrawal(); break; case 5: cus[i].transaction(cus); break; default: cout<<"\n\t\tEND OF THE OPERATION"; exit(1); } } if(flag==0) cout<<"\n\t\tYOUR ACCOUNT DOES NOT EXIST..."<<endl; } void account :: balenq() { cout<<"\n\t\tCUSTOMER NAME : "<< name << endl; cout<<"\n\t\tBALANCE : "<< amt << endl; } void account :: deposite() { int damt; cout<<"\n\t\tCUSTOMER NAME : "<< name <<endl; cout<<"\n\t\tBALANCE : "<< amt <<endl; cout<<"\n\tENTER THE AMOUNT TO BE DEPOSITED : "; cin>>damt; amt+=damt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; } void account :: withdrawal() { int wamt; cout<<"\n\t\tCUSTOMER NAME : "<< name; cout<<"\n\t\tBALANCE : "<< amt; cout<<"\n\tENTER THE AMOUNT TO BE WITHDRAWN : "; cin>>wamt; if(amt-wamt>=500) { amt-=wamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt; } else cout<<"\n\tYOUR BALANCE IS TOO LOW FOR WITHDRAWAL..."<<endl; } void account :: transaction (account cus[]) { int no,tamt,flag=0; cout<<"\n\tENTER THE RECEIVER'S ACCOUNT NUMBER : "; cin>>no; cout<<"\n\t\t ENTER THE AMOUNT : "; cin>>tamt; for(int i=0;i<=n&&flag==0;i++) if(cus[i].accno==no) { flag=1; cus[i].amt+=tamt; amt-=tamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; cout<<"\n\t\t RECEIVER'S BALANCE : "<<cus[i].amt<<endl; } if(flag==0) cout<<"\n\tRECEIVER'S ACCOUNT NUMBER IS NOT AVALIABLE..."<<endl; } void main() { account cus[10]; int ch; do { cout<<"\n\t\t BANK ACCOUNT"; cout<<"\n\t\t ************\n"; cout<<"\n\t\t1.CREATE AN ACCOUNT"; cout<<"\n\t\t2.BALANCE ENQUIRY"; cout<<"\n\t\t3.DEPOSITE"; cout<<"\n\t\t4.WITHDRAWAL"; cout<<"\n\t\t5.TRANSACTION"; cout<<"\n\t\t6.EXIT\n\n"; cout<<"\n\t\tENTER YOUR CHOICE : "; cin>>ch; if(ch==1) cus[n].create(); else accinfo(cus,ch); }while(1); }
I can not get my C++ program to work right. It is supposed to tell if a word is a palindrome or not, but it only tells thet the word is not a palindrome. And I can't fix it.
what is meant for variable not found?
What is the code for following o/p * * * * * * * * * * * * * * * *
Display this kind of output on screen. 1 0 1 1 0 1 3. Display this kind of output on screen. 1 1 0 1 0 1 4. Display this kind of output on screen. 1 1 0 1 0 1 5.Display this kind of output on screen. 1 2 3 4 5 6 7 8 9 10
void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say the output....?
Write a c-programe that input one number of four digits and find digits sum?
#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }