i have an array CAPGEMINI .....Here i need to check whether
G is there or not ..how to do that
and friends i have one big doubt that is
whether it is array or string ,how we come to know that and
where we consider that it's array ,where we consider that
it's an string
because when i want to find the length i have big doubt
whether we need to use len function or ubound ...
ans me for this TWO Questions any one please
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Answer / udayakiran
This might be the solution If we consider it as array:
ar2 = Array("C","A","P","G","E","M","I","N","I")
arlen=UBound(ar2)-lbound(ar2)+1 'Finding array length
For p= 0 to arlen-1
If strcomp(ar2(p),"G")=0 Then
msgbox "The letter G is found"
Exit For
End If
Next
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / tarakeshwar
a="CAPGEMINI"
length = len(a)
flag ="G is not present"
For i = 1 to length
res= mid(a,i,1)
if res = "G" then
flag = "G is present"
End if
Next
msgbox flag
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / arun
Please try this
Dim AR2,i
AR2 = Array("C","A","P","G","E","M","I","N","I")
For i=0 to ubound(AR2)
If AR2(i)="G" Then
msgbox "G found in Array"
End If
Next
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / gabbar
Dim a
a=array("CAPGEMINI" )
If len(join(a))<>len(Replace(join(a),"G","")) Then
msgbox "Occurance of G in array: "&len(join(a))-len(Replace(join(a),"G",""))
End If
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / koteswar
str = "CAPGEMINI"
z= "G "
flag = 0
For i = 1 to len(str)
x = mid(str, i, 1)
If Instr(1,z,x,1) Then
msgbox z
If flag = 0 Then
Reporter.ReportEvent micPass, "The required Letter is
available in the stirng", "True"
else
Reporter.ReportEvent micFail , " The required Letter is
not availabe in the string" , "False"
End If
End IF
Next
Array means It is a collection of similar objects and
enclosed with curly braces. at that time you can use Ubound
for count the no of objects are available in the given array
Srring means single or collection alphanumeric characters
enclosed with quotations. If you want to count the no of
characters in the given string you can use len()
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / rajesh
see that is my question...here you also confused, here
CAPGEMINI is a array ,not a string..give a ans please
| Is This Answer Correct ? | 1 Yes | 0 No |
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