i have table T!. A B C D NULL 1 2 3 4 NULL 5

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i have table T!.

A B C D
NULL 1 2 3
4 NULL 5 6
7 8 NULL 9
10 11 12 NULL.

I WANT COUNT OF NULL VALUES IN TABLE. WRITE A QUERY.

Question Posted / sreenu

14 Answers
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i have table T!. A B C D NULL 1 2 3 4 NULL 5 6 7 8 NULL ..

Answer / naren

select count(*) from t1 where a is null or b is null or c is
null or d is null

Is This Answer Correct ?

26 Yes

3 No

i have table T!. A B C D NULL 1 2 3 4 NULL 5 6 7 8 NULL ..

Answer / abinash_mishra

SELECT a_null + b_null + c_null + d_null
FROM (SELECT COUNT (DECODE (a, NULL, 1, NULL)) a_null,
COUNT (DECODE (b, NULL, 1, NULL)) b_null,
COUNT (DECODE (c, NULL, 1, NULL)) c_null,
COUNT (DECODE (d, NULL, 1, NULL)) d_null
FROM t_null);

Is This Answer Correct ?

6 Yes

1 No

i have table T!. A B C D NULL 1 2 3 4 NULL 5 6 7 8 NULL ..

Answer / naren

select
count(decode(a,null,1)),count(decode(b,null,1)),count(decode(c,null,1)),count(decode(d,null,1))
from t1

Is This Answer Correct ?

6 Yes

4 No

i have table T!. A B C D NULL 1 2 3 4 NULL 5 6 7 8 NULL ..

Answer / ankesh

select sum(nvl2(col1,0,1)+sum(nvl2(col2,0,1)+<...as many
columns we have > from <table name>

Is This Answer Correct ?

2 Yes

0 No

i have table T!. A B C D NULL 1 2 3 4 NULL 5 6 7 8 NULL ..

Answer / abinash_mishra

SELECT COUNT (DECODE ( a, NULL, 'a',DECODE (b,NULL, 'b',DECODE (c, NULL, 'c', DECODE (d, NULL, 'd', NULL))))) null_count
FROM t_null;

Is This Answer Correct ?

2 Yes

1 No

i have table T!. A B C D NULL 1 2 3 4 NULL 5 6 7 8 NULL ..

Answer / mathan r

create table clustering
(
id1 varchar(10),
id2 varchar(10),
id3 varchar(10)

)

insert into clustering
select '1','2',null
union
select '1',null,'3'
union all
select null,'2','3'

select sum(nullable) from
(select count(case when id1 = null then '1' else '2' end) 'nullable' from clustering where id1 is null
union all
select count(case when id2 = null then '1' else '2' end)'nullable' from clustering where id2 is null
union all
select count(case when id3 = null then '1' else '2' end)'nullable' from clustering where id3 is null ) tmp

Is This Answer Correct ?

1 Yes

0 No

i have table T!. A B C D NULL 1 2 3 4 NULL 5 6 7 8 NULL ..

Answer / ramesh

select a1+b1+c1+d1 from
(select count(case when a='null' then 1 end) a1,
count(case when b='null' then 1 end) b1,
count( case when c='null' then 1 end) c1,
count(case when d='null' then 1 end) d1 from t1)

Is This Answer Correct ?

1 Yes

0 No

i have table T!. A B C D NULL 1 2 3 4 NULL 5 6 7 8 NULL ..

Answer / gaurav

select (count(decode(A,null,1)) + count(decode (B,null,1)) + count(decode(C,null,1) + count(decode(D,null,1))) null_count
from T

Is This Answer Correct ?

1 Yes

0 No

i have table T!. A B C D NULL 1 2 3 4 NULL 5 6 7 8 NULL ..

Answer / ash

select sum(case when A is null then 1 when B is null then 1
when C is null then 1 when D is null then 1 else 0 end)as
count_null from table T

Is This Answer Correct ?

2 Yes

1 No

i have table T!. A B C D NULL 1 2 3 4 NULL 5 6 7 8 NULL ..

Answer / mani

SELECT A+B+C+D FROM
( select
count(decode(A,null,1)) A,
COUNT(DECODE (B,null,1))B,
COUNT(DECODE (C,null,1))C,
COUNT(DECODE(D,null,1)) D
from PRACTICE2);

Is This Answer Correct ?

0 Yes

0 No

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