Answer / lakshmi sreekanth

#include <stdio.h>
#include <sys/types.h>
#include <dirent.h>

main()
{
struct dirent *dp;
DIR *dfd = opendir("/home/sreekanth");

if(dfd != NULL)
{
while((dp = readdir(dfd)) != NULL)
printf("%s\n", dp->d_name);
closedir(dfd);
}
return 0;
}

Answer / muthu

please write the correct program with output...

by prof.muthu m.c.a phd etc..
ph:9962940220

Answer / rakesh

void main()
{
char path[100];
cout<<"Enter the path of directory::";
cin.getline(path,100);
system("cd path");
system("dir");
} // In windows
// For linux change dir to ls.

Answer / prince

main()
{
char path[100];
printf("Enter the path of directory:");
scanf("%s",path);
system("cd path");
system("ls");
}

main( ) { int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}}; printf(“%u %u %u %d \n”,a,*a,**a,***a); printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1); }

2 Answers  

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Give a very good method to count the number of ones in a 32 bit number. (caution: looping through testing each bit is not a solution)

7 Answers   Microsoft,

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void main() { void *v; int integer=2; int *i=&integer; v=i; printf("%d",(int*)*v); }

1 Answers   Honeywell,

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why is printf("%d %d %d",i++,--i,i--);

4 Answers   Apple, Cynity, TCS,

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What is your nationality?

1 Answers   GoDB Tech,

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#include <stdio.h> int main(void) { int a=4, b=2; a=b<<a+b>>2 ; printf("%d",a); return 0; }

0 Answers   Student,

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void main() { static int i; while(i<=10) (i>2)?i++:i--; printf(“%d”, i); }

2 Answers  

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How to count a sum, when the numbers are read from stdin and stored into a structure?

1 Answers  

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main() { int *j; { int i=10; j=&i; } printf("%d",*j); }

9 Answers   HCL, Wipro,

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void func1(int (*a)[10]) { printf("Ok it works"); } void func2(int a[][10]) { printf("Will this work?"); } main() { int a[10][10]; func1(a); func2(a); } a. Ok it works b. Will this work? c. Ok it worksWill this work? d. None of the above

1 Answers   HCL,

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program to find magic aquare using array

4 Answers   HCL,

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What is the output of the program given below main() { signed char i=0; for(;i>=0;i++) ; printf("%d\n",i); }

1 Answers  

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