Answer / guest

a) 1, if we use main|c then error, illegal use of pointer

Answer / saurabh

a. 1, bcz anything||any +ve value(except zero) is true(1).

1) int i=5; j=i++ + i++ + i++; printf("%d",j);This code gives the answer 15.But if we replace the value of the j then anser is different?why? 2)int i=5; printf("%d",i++ + i++ + i++); this givs 18.

8 Answers   IBPS, Infosys, TCS,

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main() { int *j; { int i=10; j=&i; } printf("%d",*j); }

9 Answers   HCL, Wipro,

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program to find the roots of a quadratic equation

14 Answers   College School Exams Tests, Engineering, HP, IIIT, Infosys, Rajiv Gandhi University of Knowledge Technologies RGUKT, SSC,

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Write a procedure to implement highlight as a blinking operation

2 Answers  

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what is variable length argument list?

2 Answers  

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Implement a t9 mobile dictionary. (Give code with explanation )

1 Answers   Amazon, Peak6, Yahoo,

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Program to Delete an element from a doubly linked list.

4 Answers   College School Exams Tests, Infosys,

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You are given any character string. Find the number of sets of vowels that come in the order of aeiou in the given string. For eg., let the given string be DIPLOMATIC. The answer returned must be "The number of sets is 2" and "The sets are "IO and AI". Vowels that form a singleton set must be neglected. Try to post the program executable in gcc or g++ or in java.

3 Answers  

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struct Foo { char *pName; char *pAddress; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); obj->pName = malloc(100); obj->pAddress = malloc(100); strcpy(obj->pName,"Your Name"); strcpy(obj->pAddress, "Your Address"); free(obj); printf("%s", obj->pName); printf("%s", obj->pAddress); } a. Your Name, Your Address b. Your Address, Your Address c. Your Name Your Name d. None of the above

2 Answers   HCL,

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main() { unsigned int i=65000; while(i++!=0); printf("%d",i); }

1 Answers  

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main() { int i; i = abc(); printf("%d",i); } abc() { _AX = 1000; }

2 Answers  

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struct aaa{ struct aaa *prev; int i; struct aaa *next; }; main() { struct aaa abc,def,ghi,jkl; int x=100; abc.i=0;abc.prev=&jkl; abc.next=&def; def.i=1;def.prev=&abc;def.next=&ghi; ghi.i=2;ghi.prev=&def; ghi.next=&jkl; jkl.i=3;jkl.prev=&ghi;jkl.next=&abc; x=abc.next->next->prev->next->i; printf("%d",x); }

1 Answers  

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