Display this kind of output on screen.
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3. Display this kind of output on screen.
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1 0 1
4. Display this kind of output on screen.
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1 0
1 0 1
5.Display this kind of output on screen.
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4 5 6
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Answer / vasanti
void main()
{
int i,j;
for(i=0;i<=2;i++)
{
for(j=2;j>i;j--)
printf(" ");
for(j=1;j<(i+1);j++)
{
printf("%d",mod(j-i));
}
printf("/n");
}
getch();
}
------------------------------\void main()
{
int i,j;
for(i=0;i<=2;i++)
{
// for(j=2;j>i;j--)
// printf(" ");
for(j=1;j<(i+1);j++)
{
printf("%d",mod(i-j));
}
printf("/n");
}
getch();
}
--------------------------------
void main()
{
int i,j;
for(i=0;i<=2;i++)
{
//for(j=2;j>i;j--)
// printf(" ");
for(j=1;j<(i+1);j++)
{
printf("%d",mod(j-i));
}
printf("/n");
}
getch();
}
-------------------------
void main()
{
int i,j,k=1;
for(i=0;i<=3;i++)
{
for(j=3;j>i;j--)
printf(" ");
for(j=1;j<(i+1);j++)
{
k=k+1;
printf("%d",k);
}
printf("/n");
}
getch();
}
| Is This Answer Correct ? | 1 Yes | 2 No |
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Display this kind of output on screen. 1 0 1 1 0 1 3. Display this kind of output on screen. 1 1 0 1 0 1 4. Display this kind of output on screen. 1 1 0 1 0 1 5.Display this kind of output on screen. 1 2 3 4 5 6 7 8 9 10
#include<iostream.h> #include<stdlib.h> static int n=0; class account { int age,accno; float amt; char name[20]; public: friend void accinfo(account [] ,int); void create(); void balenq(); void deposite(); void withdrawal(); void transaction(account []); }; void account :: create() { static int acc=1231; accno=acc+n; cout<<"\n\tENTER THE CUSTOMER NAME : "; cin>>name; cout<<"\n\t ENTER THE AGE : "; cin>>age; cout<<"\n\t ENTER THE AMOUNT : "; cin>>amt; // if(amt<=500) // cout<<"\n\tAMOUNT IS NOT SUFFICIENT TO CREATE AN ACCOUNT..."; cout<<"\n\t YOUR ACCOUNT NUMBER : "<<accno<<endl; n++; } void accinfo(account cus[],int ch) { int no,flag=0; cout<<"\n\t\tENTER YOUR ACCOUNT NUMBER : "; cin>>no; for(int i=0;i<=n&&flag==0;i++) if(no==cus[i].accno) { flag=1; switch(ch) { case 2: cus[i].balenq(); break; case 3: cus[i].deposite(); break; case 4: cus[i].withdrawal(); break; case 5: cus[i].transaction(cus); break; default: cout<<"\n\t\tEND OF THE OPERATION"; exit(1); } } if(flag==0) cout<<"\n\t\tYOUR ACCOUNT DOES NOT EXIST..."<<endl; } void account :: balenq() { cout<<"\n\t\tCUSTOMER NAME : "<< name << endl; cout<<"\n\t\tBALANCE : "<< amt << endl; } void account :: deposite() { int damt; cout<<"\n\t\tCUSTOMER NAME : "<< name <<endl; cout<<"\n\t\tBALANCE : "<< amt <<endl; cout<<"\n\tENTER THE AMOUNT TO BE DEPOSITED : "; cin>>damt; amt+=damt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; } void account :: withdrawal() { int wamt; cout<<"\n\t\tCUSTOMER NAME : "<< name; cout<<"\n\t\tBALANCE : "<< amt; cout<<"\n\tENTER THE AMOUNT TO BE WITHDRAWN : "; cin>>wamt; if(amt-wamt>=500) { amt-=wamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt; } else cout<<"\n\tYOUR BALANCE IS TOO LOW FOR WITHDRAWAL..."<<endl; } void account :: transaction (account cus[]) { int no,tamt,flag=0; cout<<"\n\tENTER THE RECEIVER'S ACCOUNT NUMBER : "; cin>>no; cout<<"\n\t\t ENTER THE AMOUNT : "; cin>>tamt; for(int i=0;i<=n&&flag==0;i++) if(cus[i].accno==no) { flag=1; cus[i].amt+=tamt; amt-=tamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; cout<<"\n\t\t RECEIVER'S BALANCE : "<<cus[i].amt<<endl; } if(flag==0) cout<<"\n\tRECEIVER'S ACCOUNT NUMBER IS NOT AVALIABLE..."<<endl; } void main() { account cus[10]; int ch; do { cout<<"\n\t\t BANK ACCOUNT"; cout<<"\n\t\t ************\n"; cout<<"\n\t\t1.CREATE AN ACCOUNT"; cout<<"\n\t\t2.BALANCE ENQUIRY"; cout<<"\n\t\t3.DEPOSITE"; cout<<"\n\t\t4.WITHDRAWAL"; cout<<"\n\t\t5.TRANSACTION"; cout<<"\n\t\t6.EXIT\n\n"; cout<<"\n\t\tENTER YOUR CHOICE : "; cin>>ch; if(ch==1) cus[n].create(); else accinfo(cus,ch); }while(1); }
which typw of errors ? & how to solve it ?
void main() { int i=5; printf("%d",i+++++i); }