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Set ip address as 10.30.20.1
write a script to replace the 30 with 40 ?
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Answer / s.gun
% set ip 10.30.20.1
10.30.20.1
% regsub -all {30} $ip {40} ip
1
% puts $ip
10.40.20.1
%
| Is This Answer Correct ? | 7 Yes | 3 No |
In above answer if you have IP like 10.30.30.1 then it replace for all 30 with 40.But here i guess intention is just to replace one octet with 40.So following solves that issue:
set a 10.30.2.1
set b [ string replace $a 3 4 40 ]
puts $b
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / satyanarayana
here you can do this in multiple ways
1.regsub 30 $data 40 a
puts $a
this will give you the replaced string
2.string replace $data 3 4 40
this also will give you the replaced value
| Is This Answer Correct ? | 3 Yes | 2 No |
Answer / srinubalsu
set ip 10.30.20.1
puts [join [lreplace [split $ip .] 1 1 40] .]
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / siddalingesha
set i "10.30.20.1"
set n [split $i "."]
set k [lreplace $n 1 1 40]
set s [join $k "."]
puts "$s"
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / guest
set ip "10.30.20.1"
regsub -all {m\30\M} $ip 40 ip_new
puts $ip_new
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / amarnath
set ip 10.20.30.40
set a [split $ip .]
puts $a
set oct1 [lindex $a 0]
set oct2 [lindex $a 1]
set oct3 [lindex $a 2]
set oct4 [lindex $a 3]
#set oct3 50
set ip [join "$oct1 $oct2 $oct4 $oct3" "."]
puts $ip
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / sat
Set ip 10.30.20.1
split ip using split .
from the resultant list, use lreplace command to replace
element 30 with 20.
| Is This Answer Correct ? | 3 Yes | 4 No |
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