Answer / pushkar kalantri

#include<stdio.h>
#include<string.h>

void main()
{
char
v1[11]={'X','C','O','M','P','U','T','E','R','S','\0'},p='.';
int v2[11]={0,1,2,3,4,5,6,7,8,9};
char ip[10];
int n,i,j,k=0,cnt=0;
//clrscr();

printf("Enter coded value: ");
scanf("%s",ip);

// printf("\nur entered code = %s",ip);
printf("\nUr price is = ");


for(i=0;v1[i]!='\0';i++)
{
if(ip[k]=='.')
{
++k;
printf("%c",p);
}
if(ip[k]==v1[i])
{
printf("%d",i);
++k;
i=-1;
if(ip[k]=='\0')
break;
}
}
}
//compiled by GCC

Answer / levixnu

#include<stdio.h>
#include<string.h>
#include<conio.h>

void main()
{
char
v1[11]={'X','C','O','M','P','U','T','E','R','S','\0'},p='.';
int v2[11]={0,1,2,3,4,5,6,7,8,9};
char ip[10];
int n,i,j,k=0,cnt=0;
clrscr();

printf("Enter coded value: ");
scanf("%s",ip);

printf("\nur entered code = %s",ip);
printf("\nUr price is = ");


for(i=0;v1[i]!='\0';i++)
{
if(ip[k]=='.')
{
++k;
printf("%c",p);
}
if(ip[k]==v1[i])
{
printf("%d",i);
++k;
i=-1;
if(ip[k]=='\0')
break;
}
}
getch();
}

Answer / roxy

#include<stdio.h>
#include<string.h>

main()
{
char v1[11]={'X','C','O','M','P','U','T','E','R','S','\0'};
char v2[11]={'0','1','2','3','4','5','6','7','8','9','\0'};

int n;
clrscr();

printf("Enter coded value: ");
scanf("%s",v1);

n=strncpy(v1, v2, 1);

v2[1]='\0';

printf("\nTag Price: %s ",v2);

getch();
}

difference between c/c++ programing language? what is necessesity of c++ when existing c programing language?

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what is meant by linking error? how can i solve it? if there is a linking error " unable to open file 'cos.obj'? then what should i do?

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what is exceptions?

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Given that two int variables, total and amount , have been declared, write a sequence of statements that: initializes total to 0 reads three values into amount , one at a time. After each value is read in to amount , it is added to the value in total (that is, total is incremented by the value in amount ). Instructor's notes: If you use a loop, it must be a for loop. And if you use a loop control variable for counting, you must declare it.

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2 Answers  

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Given that two int variables, total and amount, have been declared, write a loop that reads integers into amount and adds all the non-negative values into total. The loop terminates when a value less than 0 is read into amount. Don't forget to initialize total to 0. Instructor's notes: This problem requires either a while or a do-while loop.

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To generate the series 1+3+5+7+... using C program

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#include"stdio.h" #include"conio.h" void main() { int a; printf("\n enter a number:"); scanf("%c\n"); getch(); }

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Given an int variable n that has already been declared and initialized to a positive value, and another int variable j that has already been declared, use a do...while loop to print a single line consisting of n asterisks. Thus if n contains 5, five asterisks will be printed. Use no variables other than n and j .

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What are the different types of errors in C and when they occur?

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