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write a program to compare 2 numbers without using logical
operators?
- 5 Answers
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Answer / bashu
main()
{
int x,y;
sf("%d,%d",&x,&y);
if(x^y)
pf("not equal");
else
pf("equal");
}
| Is This Answer Correct ? | 39 Yes | 22 No |
Answer / faceless
main()
{
int result, sign_bit_num;
unsigned int x, y;
sign_bit_num = sizeof(int)*8 ;
result = x-y;
if (result) {
result = result >> (sign_bit_num-1);
if (result) {
printf("x less than y");
} else {
printf("x greater than y");
}
} else {
printf("equal");
}
| Is This Answer Correct ? | 14 Yes | 8 No |
Answer / rishabh
#include<stdio.h>
#include<limits.h>
int sign(int number)
{
return (unsigned) number / (unsigned) INT_MIN;
}
int main(int argc, char *argv[])
{
int a = atoi(argv[1]);
int b = atoi(argv[2]);
int dif = a - b;
int sb1 = sign(dif);
int sb2 = sign(dif - 1) - sb1;
int ptr = 2 * sb2 + sb1;
char *messages[3] =
{
"%d is greater than %d",
"%d is less than %d",
"%d is equal to %d" };
printf(messages[ptr], a, b);
}
}
| Is This Answer Correct ? | 3 Yes | 4 No |
Answer / jj
unsigned int is_same(unsigned int a, unsigned int b)
{
return (a / b);
}
int main()
{
unsigned int a, b;
a = 40, b = 40;
if ( is_same(a,b) == 1 )?
cout << "Equal" << endl
:
cout << "Not equal" << endl;
return 0;
}
| Is This Answer Correct ? | 0 Yes | 5 No |
Answer / r.aruna
#include<stdio.h>
#include<conio.h>
void main()
{
int a;
int b;
clrscr();
printf("enter the a value=");
scanf("%d",&a);
printf("enter the b value=");
scanf("%d",&b);
if(a==b)
{
printf("a is greater");
}
else
{
printf("b is greater");
}
getch();
}
| Is This Answer Correct ? | 4 Yes | 15 No |
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