Answer / susie

Answer :

1

Explanation:

Arrays cannot be passed to functions as arguments and only
the pointers can be passed. So the argument is equivalent to
int * array (this is one of the very few places where [] and
* usage are equivalent). The return statement becomes,
sizeof(int *)/ sizeof(int) that happens to be equal in this
case.

Answer / manoj kumar

Arrays cannot be passed to functions as arguments and only
the pointers can be passed.

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