int DIM(int array[])

{

return sizeof(array)/sizeof(int );

}

main()

{

int arr[10];

printf(“The dimension of the array is %d”, DIM(arr));

}




Answers were Sorted based on User's Feedback



int DIM(int array[]) { return sizeof(array)/sizeof(int ); } mai..

Answer / susie

Answer :

1

Explanation:

Arrays cannot be passed to functions as arguments and only
the pointers can be passed. So the argument is equivalent to
int * array (this is one of the very few places where [] and
* usage are equivalent). The return statement becomes,
sizeof(int *)/ sizeof(int) that happens to be equal in this
case.

Is This Answer Correct ?    8 Yes 1 No

int DIM(int array[]) { return sizeof(array)/sizeof(int ); } mai..

Answer / manoj kumar

Arrays cannot be passed to functions as arguments and only
the pointers can be passed.

Is This Answer Correct ?    1 Yes 0 No

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