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What is the subtle error in the following code segment?

void fun(int n, int arr[])

{

int *p=0;

int i=0;

while(i++<n)

p = &arr[i];

*p = 0;

}



What is the subtle error in the following code segment? void fun(int n, int arr[]) ..

Answer / susie

Answer : & Explanation:

If the body of the loop never executes p is assigned no
address. So p remains NULL where *p =0 may result in problem
(may rise to runtime error “NULL pointer assignment” and
terminate the program).

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