Answer / chuck dorris

#include <string>
#include <sstream>

std::string lookandsay(const std::string &s)
{
std::ostringstream r;

for (unsigned int i = 0; i != s.length(); ) {
unsigned int new_i = s.find_first_not_of(s[i], i+1);
if (new_i == std::string::npos)
new_i = s.length();

r << new_i - i << s[i];
i = new_i;
}
return r.str();
}

#include <iostream>

int main()
{
std::string laf = "1";

std::cout << laf << std::endl;
for (int i = 0; i < 10; i++) {
laf = lookandsay(laf);
std::cout << laf << std::endl;
}

return 0;
}

int main() { int x=10; printf("x=%d, count of earlier print=%d", x,printf("x=%d, y=%d",x,--x)); getch(); } ================================================== returns error>> ld returned 1 exit status =================================================== Does it have something to do with printf() inside another printf().

2 Answers  

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void main() { while(1){ if(printf("%d",printf("%d"))) break; else continue; } }

1 Answers  

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write a c program to print magic square of order n when n>3 and n is odd?

1 Answers   HCL,

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3) Int Matrix of certain size was given, We had few valu= es in it like this. =97=97=97=97=97=97=97=97=97=97=97 1 = | 4 | | 5 | &= nbsp; | 45 =97=97=97=97=97=97=97=97=97=97=97 &n= bsp; | 3 | 3 | 5 | = | 4 =97=97=97=97=97=97=97=97=97=97=97 34 |&nbs= p; 3 | 3 | | 12 | &= nbsp; =97=97=97=97=97=97=97=97=97=97=97 3 | &nbs= p; | 3 | 4 | = | 3 =97=97=97=97=97=97=97=97=97=97=97 3 | = ; | | | = ; 3 | =97=97=97=97=97=97=97=97=97=97=97 &= nbsp; | | 4 | = ; | 4 | 3 We w= ere supposed to move back all the spaces in it at the end. Note: = If implemented this prog using recursion, would get higher preference.

0 Answers   RoboSoft,

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void main() { int c; c=printf("Hello world"); printf("\n%d",c); }

2 Answers  

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Give a very good method to count the number of ones in a 32 bit number. (caution: looping through testing each bit is not a solution)

7 Answers   Microsoft,

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main() { int i=4,j=7; j = j || i++ && printf("YOU CAN"); printf("%d %d", i, j); }

1 Answers  

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why java is platform independent?

13 Answers   Wipro,

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#ifdef something int some=0; #endif main() { int thing = 0; printf("%d %d\n", some ,thing); }

1 Answers  

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Declare an array of N pointers to functions returning pointers to functions returning pointers to characters?

1 Answers  

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main() { int a=2,*f1,*f2; f1=f2=&a; *f2+=*f2+=a+=2.5; printf("\n%d %d %d",a,*f1,*f2); }

6 Answers  

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#include<stdio.h> main() { struct xx { int x=3; char name[]="hello"; }; struct xx *s=malloc(sizeof(struct xx)); printf("%d",s->x); printf("%s",s->name); }

1 Answers   TCS,

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