Answer / susie

Answer :

bye

Explanation:

ptr is array of pointers to functions of return type
int.ptr[0] is assigned to address of the function aaa.
Similarly ptr[1] and ptr[2] for bbb and ccc respectively.
ptr[2]() is in effect of writing ccc(), since ptr[2] points
to ccc.

#include<stdio.h> main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); }

1 Answers  

---

void func1(int (*a)[10]) { printf("Ok it works"); } void func2(int a[][10]) { printf("Will this work?"); } main() { int a[10][10]; func1(a); func2(a); } a. Ok it works b. Will this work? c. Ok it worksWill this work? d. None of the above

1 Answers   HCL,

---

What are the following notations of defining functions known as? i. int abc(int a,float b) { /* some code */ } ii. int abc(a,b) int a; float b; { /* some code*/ }

1 Answers  

---

Write a prog to accept a given string in any order and flash error if any of the character is different. For example : If abc is the input then abc, bca, cba, cab bac are acceptable, but aac or bcd are unacceptable.

5 Answers   Amazon, Microsoft,

---

String copy logic in one line.

11 Answers   Microsoft, NetApp,

---

How will u find whether a linked list has a loop or not?

8 Answers   Microsoft,

---

Give a one-line C expression to test whether a number is a power of 2.

10 Answers   Microsoft,

---

posted by surbhi just now main() { float a = 5.375; char *p; int i; p=(char*)&a; for(i=0;i<=3;i++) printf("%02x",(unsigned char) p[i]); } how is the output of this program is :: 0000ac40 please let me know y this output has come

2 Answers   GATE,

---

main( ) { int a[ ] = {10,20,30,40,50},j,*p; for(j=0; j<5; j++) { printf(“%d” ,*a); a++; } p = a; for(j=0; j<5; j++) { printf(“%d ” ,*p); p++; } }

1 Answers  

---

#define DIM( array, type) sizeof(array)/sizeof(type) main() { int arr[10]; printf(“The dimension of the array is %d”, DIM(arr, int)); }

1 Answers  

---

#include<stdio.h> main() { int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} }; int *p,*q; p=&a[2][2][2]; *q=***a; printf("%d..%d",*p,*q); }

1 Answers  

---

main() { int k=1; printf("%d==1 is ""%s",k,k==1?"TRUE":"FALSE"); }

1 Answers  

---