Answer / susie

Answer :

Linker error: undefined symbol '_i'.

Explanation:

extern declaration specifies that the variable i is defined
somewhere else. The compiler passes the external variable to
be resolved by the linker. So compiler doesn't find an
error. During linking the linker searches for the definition
of i. Since it is not found the linker flags an error.

Answer / sahoo845

This program throws error in compilation. Because variable i is declared but not defined anywhere. Essentially, the variable isn’t allocated any memory. And the program is trying to change the value to 20 of a variable that doesn’t exist at all.

main() { signed int bit=512, i=5; for(;i;i--) { printf("%d\n", bit >> (i - (i -1))); } } a. 512, 256, 0, 0, 0 b. 256, 256, 0, 0, 0 c. 512, 512, 512, 512, 512 d. 256, 256, 256, 256, 256

2 Answers   HCL,

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Code for 1>"ascii to string" 2>"string to ascii"

1 Answers   Aricent, Global Logic,

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main() { char p[ ]="%d\n"; p[1] = 'c'; printf(p,65); }

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to remove the repeated cahracter from the given caracter array. i.e.., if the input is SSAD output should of SAD

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#define int char main() { int i=65; printf("sizeof(i)=%d",sizeof(i)); }

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#include<stdio.h> main() { register i=5; char j[]= "hello"; printf("%s %d",j,i); }

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main() { signed int bit=512, i=5; for(;i;i--) { printf("%d\n", bit = (bit >> (i - (i -1)))); } } a. 512, 256, 128, 64, 32 b. 256, 128, 64, 32, 16 c. 128, 64, 32, 16, 8 d. 64, 32, 16, 8, 4

2 Answers   HCL,

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