Answer / susie

Answer :

11

Explanation:

the expression i+++j is treated as (i++ + j)

Answer / amita

error

main() { unsigned char i=0; for(;i>=0;i++) ; printf("%d\n",i); }

1 Answers  

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void main() { while(1){ if(printf("%d",printf("%d"))) break; else continue; } }

1 Answers  

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union u { union u { int i; int j; }a[10]; int b[10]; }u; main() { printf("\n%d", sizeof(u)); printf(" %d", sizeof(u.a)); // printf("%d", sizeof(u.a[4].i)); } a. 4, 4, 4 b. 40, 4, 4 c. 1, 100, 1 d. 40 400 4

3 Answers   HCL,

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func(a,b) int a,b; { return( a= (a==b) ); } main() { int process(),func(); printf("The value of process is %d !\n ",process(func,3,6)); } process(pf,val1,val2) int (*pf) (); int val1,val2; { return((*pf) (val1,val2)); }

1 Answers   Satyam,

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What is the problem with the following code segment? while ((fgets(receiving array,50,file_ptr)) != EOF) ;

1 Answers  

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Write a program to receive an integer and find its octal equivalent?

7 Answers  

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#include<stdio.h> main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); }

1 Answers  

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write the function. if all the character in string B appear in string A, return true, otherwise return false.

11 Answers   Google,

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main( ) { void *vp; char ch = ‘g’, *cp = “goofy”; int j = 20; vp = &ch; printf(“%c”, *(char *)vp); vp = &j; printf(“%d”,*(int *)vp); vp = cp; printf(“%s”,(char *)vp + 3); }

1 Answers  

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main() { int i=3; switch(i) { default:printf("zero"); case 1: printf("one"); break; case 2:printf("two"); break; case 3: printf("three"); break; } }

1 Answers  

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main(int argc, char *argv[]) { (main && argc) ? main(argc-1, NULL) : return 0; } a. Runtime error. b. Compile error. Illegal syntax c. Gets into Infinite loop d. None of the above

4 Answers   HCL, LG,

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How we will connect multiple client ? (without using fork,thread)

3 Answers   TelDNA,

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