Answer / susie

Answer :

Compiler error: Undefined label 'here' in function main

Explanation:

Labels have functions scope, in other words the scope of the
labels is limited to functions. The label 'here' is
available in function fun() Hence it is not visible in
function main.

main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); } int i;

1 Answers  

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What is the subtle error in the following code segment? void fun(int n, int arr[]) { int *p=0; int i=0; while(i++<n) p = &arr[i]; *p = 0; }

1 Answers  

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hello sir,is there any function in C that can calculate number of digits in an int type variable,suppose:int a=123; 3 digits in a.what ll b answer?

6 Answers  

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main() { int a=2,*f1,*f2; f1=f2=&a; *f2+=*f2+=a+=2.5; printf("\n%d %d %d",a,*f1,*f2); }

6 Answers  

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main() { char s[ ]="man"; int i; for(i=0;s[ i ];i++) printf("\n%c%c%c%c",s[ i ],*(s+i),*(i+s),i[s]); }

1 Answers   DCE,

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Is the following statement a declaration/definition. Find what does it mean? int (*x)[10];

1 Answers  

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Give a oneline C expression to test whether a number is a power of 2?

25 Answers   EA Electronic Arts, Google, Motorola,

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respected sir, i did my MCA in 2013 when i am going to attend to an interview i was asked about my project how will i explain my project could please help me in this and my project title is "Social Networking Site For Social Responsibility"

1 Answers   Genpact, Ozdocs,

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There is a lucky draw held every day. if there is a winning number eg 1876,then all possible numbers like 1867,1687,1768 etc are the numbers that match irrespective of the position of the digit. Thus all these numbers qualify fr the lucky draw prize Assume there is no zero digit in any numbers. write a program to show all the possible winning numbers if a "winning number"is passed as an arguments to the function.

1 Answers   Nagarro,

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#define prod(a,b) a*b main() { int x=3,y=4; printf("%d",prod(x+2,y-1)); }

1 Answers  

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main() { int i; clrscr(); printf("%d", &i)+1; scanf("%d", i)-1; } a. Runtime error. b. Runtime error. Access violation. c. Compile error. Illegal syntax d. None of the above

1 Answers   HCL,

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main( ) { void *vp; char ch = ‘g’, *cp = “goofy”; int j = 20; vp = &ch; printf(“%c”, *(char *)vp); vp = &j; printf(“%d”,*(int *)vp); vp = cp; printf(“%s”,(char *)vp + 3); }

1 Answers  

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