Answer / abdul ahad

45545

because the expiration will executed from right to left and will print from left to right.

at the execution time from right i=5,--i=4,++i=5,i--=5 then decremented to4,now i++=4 ,then incremented to 5.

So the output will be left to right 45545

Answer / prashant nair

Ans: It really much more depend on compiler.


The logic/rules made should take us to the answer 45545 but compiler does also give answer as 45555 :O 

source:
http://code.hackerearth.com/bddbb9e
http://ideone.com/t5fbbd

Answer / susie

Answer :

45545

Explanation:

The arguments in a function call are pushed into
the stack from left to right. The evaluation is by popping
out from the stack. and the evaluation is from right to
left, hence the result.

Answer / jaya

ans:- 45545

Answer / rishit

And will be
4 5 5 4 5 and 1 garbage value as there are
6 %d in printf statement

Answer / moschops

This is UNSPECIFIED BEHAVIOUR. It's possible to work out exactly what your particular compiler decided to do this one particular time, but other compilers are free to do it differently (and probably will). Put the code into some different compilers and you'll see different results. The order that parameters are evaluated is unspecified and left up to the compiler.

If you can explain what the compiler happens to do this one particular time, that's nice but completely useless, but anyone who actually wrote code like this should be fired.

Answer / dharmendra

(i++,i--,++i,--i,i)
(4 , 5, 5 , 4 ,5)

explanation:
executed from right to left
and
print left to right.

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