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main()
{
int i=5;
printf("%d%d%d%d%d%d",i++,i--,++i,--i,i);
}
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Answer Posted / moschops
This is UNSPECIFIED BEHAVIOUR. It's possible to work out exactly what your particular compiler decided to do this one particular time, but other compilers are free to do it differently (and probably will). Put the code into some different compilers and you'll see different results. The order that parameters are evaluated is unspecified and left up to the compiler.
If you can explain what the compiler happens to do this one particular time, that's nice but completely useless, but anyone who actually wrote code like this should be fired.
| Is This Answer Correct ? | 10 Yes | 6 No |
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