simple c program for 12345 convert 54321 with out using string
Answers were Sorted based on User's Feedback
Answer / vignesh1988i
hi good morning folks... happy sunday.......
#include<stdio.h>
#include<conio.h>
void main()
{
int n,m;
printf("enter the number :");
scanf("%d",&n);
for(int i=1;n>0;i++)
{
m=n%10;
n=n/10;
printf("\n %d",m);
}
getch();
}
thank u
Is This Answer Correct ? | 31 Yes | 11 No |
Answer / sreenivas
#include<stdio.h>
main()
{
long n=12345,r=0;
while(n)
{
r=r*10+n%10;
n=n/10;
}
printf("%ld",r);
}
Is This Answer Correct ? | 13 Yes | 2 No |
Answer / abhradeep chatterjee
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j;
printf("enter a number");
scanf("%d",&i);
for(int n=1;n<=5;n++)
{
j=i%10;
i=i/10;
printf("%d",j);
}
getch();
}
Is This Answer Correct ? | 5 Yes | 2 No |
Answer / sharan
#include<stdio.h>
//#include<conio.h>
void main()
{
int n,m;
printf("enter the number :");
scanf("%d",&n);
while (n)
{
m=n%10;
n=n/10;
printf("%d",m);
}
printf("\n");
}
Is This Answer Correct ? | 7 Yes | 4 No |
Answer / ruchi
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int n,r,s=0,i=0,m,r1,m1,m2,p,d,s1;
clrscr();
printf("enter the number ");
scanf("%d",&n);
m=n;
while(n>0)
{
r=n%10;
n=n/10;
i=i+1;
}
m1=m%10;
d=m/10;
p=m1*pow(10,i=i-1);
while(d>=10)
{
m2=d%10;
d=d/10;
s=(s+m2*pow(10,i=i-1));
}
s1=(s+p+d*pow(10,i=i-1));
printf("%d",s1);
getch();
}
Is This Answer Correct ? | 3 Yes | 0 No |
Answer / mohit
#include<stdio.h>
#include<conio.h>
main()
{
long int num,x=0;
int b;
while(n>0)
{
b=num%10;
num=num/10;
x=x*10+b;
}
printf("new number=%ld",x);
getch();
}
Is This Answer Correct ? | 3 Yes | 0 No |
Answer / rajan sonvane
#include<stdio.h>
#include<conio.h>
main()
{
int *p,a[5]={1,2,3,4,5},b[5],i=0;
p=a;
while(i<5)
{
b[i]=*(p+4-i);
i++;
}
for(i=0; i<5; i++)
{
printf("%d",b[i]);
}
getch();
}
Is This Answer Correct ? | 1 Yes | 0 No |
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