What is the four-digit number in which the first digit is
1/3 of the second, the third is the sum of the first and
second, and the last is three times the second?
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Answer / guest
The 4 digit number is 1349.
It is given that the first digit is 1/3 of the second. There
are 3 such possibilities.
1. 1 and 3
2. 2 and 6
3. 3 and 9
Now, the third digit is the sum of the first and second digits.
1. 1 + 3 = 4
2. 2 + 6 = 8
3. 3 + 9 = 12
It is clear that option 3 is not possible. So we are left
with only two options. Also, the last digit is three times
the second, which rules out the second option. Hence, the
answer is 1349.
| Is This Answer Correct ? | 69 Yes | 2 No |
Answer / nessa
first=f,second=s,third=T,Last=L
f=s/3
T=f+s
L=3s
since s is divisible by 3,so s can be 3,6,9
Taking s=3
f=1
T=3+1=4
L=3*3=9
so answer is 1349
| Is This Answer Correct ? | 5 Yes | 1 No |
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