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Find the smallest number such that if its rightmost digit
is placed at its left end, the new number so formed is
precisely 50% larger than the original number.
- 9 Answers
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Answer / louis
you interverted 2 digits:
from 285174, it becomes 428517 (and not 428571)
the correct number is much bigger:
285714285714285714285714285714285714285714
(check with precision of long;)
| Is This Answer Correct ? | 4 Yes | 2 No |
Answer / martin zhu
105263157894736842 x2=210526315789473684
210526315789473684
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / monkey
its 285174
428571-285714 = 142857
142857 * 2 = 285714
| Is This Answer Correct ? | 5 Yes | 6 No |
Answer / harjit
You guys have specified the answer, but how you reached at
this smallest number is still a mystery. Please explain how
you reached at this answer.
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / mir dawood ali
Sorry for the mistake guys.
The right answer to the question is 142.
If we place 2 on the left most side, then it results in 214 which is 50.7042% larger than the original number.
The % difference as that of my previous answer of 213.
SO the right answer is 142.
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / kapil
There is no solution to this question in integer format
try doing the mathematical proof of it... you will come to know
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / mir dawood ali
I think the answer to this question is 213.
If we place 3 on the left most side, then the resulting number would be 321 which is 50.7042% larger than the original number.
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / justin weeks
Precisely 50% is not possible, but approximately 50% is. Little number is 2143 and big number is 3214. Exact ratio is 1.4997667.
| Is This Answer Correct ? | 0 Yes | 7 No |
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