Answer / neeta dhakad

We can create 128 subnets and subnetmask 255.255.254.0

Answer / suresh

subnetmask is 255.255.252.0, we can create 4 subnet and
atleast we can connect 500host per network

Answer / r.k.gupta

Hi Everyone
some guys give ans correctly but not in details.
so i describing in details and 100% correct.

given net id 131.112.0.0
default s/m- 255.255.0.0/16
but we need 500 hosts /network so
s/m 255.255.254.0/23
block size=2
no of networks=128
we need 500 hosts per network. so we can be on 9 bits for
host from 32 bits to fullfil our requrements(500 hosts). 9
bits on means 512. but valid host=510

1st Network is 131.112.0.0
starting ip- 131.112.0.1
Ending ip -131.112.1.254
broadcast address- 131.112.1.255

2nd Network is 131.112.2.0
starting ip - 131.112.2.1
ending ip - 131.112.3.254
broadcast add- 131.112.3.255

3rd Network - 131.112.4.0 and so on
now solved this ques.

Answer / yogesh

128 subnets and subnet mask 255.255.254.0

Answer / suresh

we can create 64 subnet sunbet mask 255.255.252.0 for
500host per network

Answer / technologist

sorry typing mistake in above answer


hi guys
we can creat 128 subnet
and subnet mask will b 255.255.254.0

Answer / tushar

131.112.0.0 this ip add is from class B
Defualt sumbet mask is 255.255.0.0

We have 500 hosts per network
so, las 9 digit required for 512 hosts per network
Remaing 7 digit is used for subnetworks

Subnet mask will b 255.255.254.0 (Becz we have total
16+7= 23 digits)
we can creat 128 subnet (Becz we have 23 digits)

and remaing 9 digits for hosts per subnetwork.

No.of subnets Range of ip

1. 131.112.0.0 to 131.112.1.255
2. 131.112.2.0 to 131.112.3.255
3. 131.112.4.0 to 131.112.5.255
4.
--
--
128. 131.112.254.0 to 131.112.255.255

Answer / rames

Here, 9 bits are required to get 500 hosts. Now, there will
be 7 bits available for the subnetting( i.e in the third
byte) so, we can create 254 subnets and 500 hosts per each
subnet with the given network ID (131.112.0.0)

Here, the subnet mask will be varying from
131.112.2.0/7 to 131.112.254.0/7 according to the no. of
bits we use for the subnetting in the third byte.

Answer / gaurav verma

If you need to divide it up into the maximum number of
subnets containing at least 500 hosts each, you should use a
/23 subnet mask. This will provide you with 128 networks of
510 hosts each. If you used a /24 mask, you would be limited
to 254 hosts. Similarly, a /22 mask would be wasteful,
allowing you 1022 hosts.

Answer / sivakumar

subnet mask is 255.255.0.0
networsk =128
host per network =510+2=512 another 2 is one brodcast ID
and an other one is network ID
starting ip of the adress 131.112.0.1
last ip of the adress 131.112.254.255

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