You have the following Network ID: 131.112.0.0. You need at
least 500 hosts per network. How many networks can you
create? What subnet mask will you use
Answers were Sorted based on User's Feedback
Answer / shankar
In Class B Network We can create 128 subnet and subnet mask
is 255.255.254.0
As of my calculation it is the best way to use in live
network.
Is This Answer Correct ? | 3 Yes | 0 No |
Answer / james
Simplest answer:
2^9 -2 will give you 510 host.
9 is # of bits
so, it will be 255.255.254.0
Subnet mask go by 128, 192, 224, 240, 248, 252, 254, 255
254 - 252 (pervious subnet mask) = 2
so network is increment of 2 starting from 0
We know that 2*128 -1 = 255 (max allow network) hint: .255
No.of subnets Range of ip
1. 131.112.0.0 to 131.112.1.255
2. 131.112.2.0 to 131.112.3.255
3. 131.112.4.0 to 131.112.5.255
4.
--
--
128. 131.112.254.0 to 131.112.255.255
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / biswanath
126 subnets can be create and subnet mask will be 255.255.254.0
Is This Answer Correct ? | 21 Yes | 21 No |
Answer / jeewan singh
I subnet mask is 132.112.1.255
we have 9 bit
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / k asif ahmed
we need 500 host
13.112.0.0
11111110.00000000
2^n=2^7=128 subnetwork
2^n-2=2^9-2=512-2=510 host/subnetwork
then the subnet mask is
255.255.254.0
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / durgesh kumar gupta
subnetmask 255.255.254.0,
networks 126,
host per subnet 510,
1st ip of the 1st subnet 131.112.2.1,
last ip of the 1st subnet 131.112.3.254
Is This Answer Correct ? | 6 Yes | 8 No |
Answer / barathiraj
We can create 126 subnets and subnetmask 255.255.254.0
Is This Answer Correct ? | 4 Yes | 6 No |
Answer / technologist
hi guys
we can creat 128 subnet
and subnet mask will b 255.255.252.0
Is This Answer Correct ? | 3 Yes | 7 No |
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