Answer Posted / r.k.gupta

Hi Everyone
some guys give ans correctly but not in details.
so i describing in details and 100% correct.

given net id 131.112.0.0
default s/m- 255.255.0.0/16
but we need 500 hosts /network so
s/m 255.255.254.0/23
block size=2
no of networks=128
we need 500 hosts per network. so we can be on 9 bits for
host from 32 bits to fullfil our requrements(500 hosts). 9
bits on means 512. but valid host=510

1st Network is 131.112.0.0
starting ip- 131.112.0.1
Ending ip -131.112.1.254
broadcast address- 131.112.1.255

2nd Network is 131.112.2.0
starting ip - 131.112.2.1
ending ip - 131.112.3.254
broadcast add- 131.112.3.255

3rd Network - 131.112.4.0 and so on
now solved this ques.

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