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Base class has two public data members. How can i derive a
new class with one datamember as public and another data
member as private?.
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Answer / deepak sharma
class base
{
public:
base(int d1 = 5, int d2 = 6) : data1(d1), data2(d2)
{ }
int data1, data2;
};
class der:public base
{
private:
using base::data1; //Making data1 of class base
private, explicitliy,
//you can make member functions private or
protected this way
};
int main(int argc, char* argv[])
{
der obj1;
cout<<obj1.data1<<endl; //Error : 'data1' : cannot
access private member declared in class 'der'
cout<<obj1.data2<<endl; //Works fine
return 0;
}
| Is This Answer Correct ? | 9 Yes | 0 No |
Answer / iyappan
just have a look on the given program. Then you can get
idea about it.
class base
{
public:
virtual void fun1(){printf("I am base class public
fun1");}
virtual void fun2(){printf("I am base class public
fun2");}
};
class derived:public base
{
void fun1(){printf("I am derived class private
fun1");}
public:
void fun2(){printf("I am derived class public
fun2");}
};
int main()
{
derived obj;
obj.fun1();//it will show compile time error.
because this is private member of derived class
obj.fun2();//it will work fine.
base *ptr = &obj;
ptr->fun1();//it will work fine.
ptr->fun2();//it will work fine.
}
| Is This Answer Correct ? | 2 Yes | 3 No |
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