Answer / biplab sinha

2nChoosen/(n+1)

Answer / a.s.

it's Ω((4^n)/(n^(3/2)))

Answer / ss

it is 2^n-n trees.

Answer / maverick

answer: 2^n-2

Answer / v.suresh kumar

It is possible to form 2^n - 1 binary trees with n nodes.

Answer / rk

2^n-1

main() { if (!(1&&0)) { printf("OK I am done."); } else { printf("OK I am gone."); } } a. OK I am done b. OK I am gone c. compile error d. none of the above

3 Answers   HCL,

Write out a function that prints out all the permutations of a string. For example, abc would give you abc, acb, bac, bca, cab, cba. You can assume that all the characters will be unique.

5 Answers   IITR, Microsoft, Nike,

#define DIM( array, type) sizeof(array)/sizeof(type) main() { int arr[10]; printf(“The dimension of the array is %d”, DIM(arr, int)); }

1 Answers  

Is the following statement a declaration/definition. Find what does it mean? int (*x)[10];

1 Answers  

main() { int a=2,*f1,*f2; f1=f2=&a; *f2+=*f2+=a+=2.5; printf("\n%d %d %d",a,*f1,*f2); }

6 Answers  

void main() { int i; char a[]="\0"; if(printf("%s\n",a)) printf("Ok here \n"); else printf("Forget it\n"); }

3 Answers   Accenture,

Write a routine to implement the polymarker function

0 Answers   TCS,

main() { struct date; struct student { char name[30]; struct date dob; }stud; struct date { int day,month,year; }; scanf("%s%d%d%d", stud.rollno, &student.dob.day, &student.dob.month, &student.dob.year); }

1 Answers  

#include<stdio.h> main() { struct xx { int x=3; char name[]="hello"; }; struct xx *s=malloc(sizeof(struct xx)); printf("%d",s->x); printf("%s",s->name); }

1 Answers   TCS,

You are given any character string. Find the number of sets of vowels that come in the order of aeiou in the given string. For eg., let the given string be DIPLOMATIC. The answer returned must be "The number of sets is 2" and "The sets are "IO and AI". Vowels that form a singleton set must be neglected. Try to post the program executable in gcc or g++ or in java.

3 Answers  

void main() { int i=i++,j=j++,k=k++; printf(“%d%d%d”,i,j,k); }

1 Answers  

&#8206;#define good bad main() { int good=1; int bad=0; printf ("good is:%d",good); }

2 Answers