U have a Scenario and there is box to enter values from 0
to 1000.
Now what is the Test data u will test?
What are the positive and negative test cases?
How will U use Equivalence class Partition ?
Answers were Sorted based on User's Feedback
Answer / jaja
*Equivalance Class Partitioning*
The Equivalance class partitioning is 'Divide the input
domail in to different classes of values.
Let me explain.
Here u have the input values from 0-1000; are u going to
insert all the values from 0 to 1000? no. we never do like
that. So here we can use the concept of Eqivalance
partitioning.
1. First Class
Single digit numbers
2. Second Class.
Two Digit numbers
3. Third Class
Three digit NUmbers
And so on .
Here also u don't want to take all single, two and three
digit nubers. use selected numbers.
This is the basic concept of Equivalace Class partitioning.
Is This Answer Correct ? | 2 Yes | 0 No |
Answer / shivanibehere
1) Suppose We have values from 0 to 1000.
2) Test Data should be like this---
1--Check for -1 (Min.-1 Value)
2--Check for 0 (Equal Value)
3--Check for 1 (Min. +1 Value)
4--Check for 999 (Max. -1 Value)
5--Check for 1000 (Equal Value)
6--Check for 1001 (Max. +1 Value)
In this way Positive and Negative Test cases are considered
and foe 0 to 1000 data values we use 6 Equivalence Class
Partition.
Is This Answer Correct ? | 3 Yes | 1 No |
Answer / rao
I too agree with Guest.What answer given by shivani is
wrong,she has given the answer for BVA.Here I am giving the
answer as per my understanding on Eq Classs Partitioning.
Here we have the inputs from 0-1000.So that,we can devide
the inputs into 1 valid calss and two invalid classes.
Valid Class is inputs are{0,any value between 0 and
1000,1000)
First Invalid class is {All the nagative values,which are
less than 0.Ex:-1)
Second invalid class is {All the positive values,which are
more than 1000,ex:1001)
Please correct me,if I am wrong.
Is This Answer Correct ? | 3 Yes | 1 No |
Answer / pulu
There ll be three input classes
1.less than zero(-1) Positive test case
2.eqaul to ge=iven condition (0 - 1000) Positive test case
3.greater than 1000 (1001) Positive test case
There ll be three test data parameter -1,3,1001.
Negative test data parameter:
1. 0.001
2. 000.1
3. 1.000
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / guest
hi shivani check with your answer i think what u told is
BVA but not Equilance class partition.
Is This Answer Correct ? | 1 Yes | 1 No |
Answer / kalii kali
actully i think dat there is no need to do such things, coz
user know what to do or not............
it is his problem ............
Is This Answer Correct ? | 0 Yes | 2 No |
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