Answer / manuswami

for file in `ls` ; do NEW=`echo $file | sed 's/.txt/.my/g'`
; mv $file $NEW ; done

Answer / akshay telang

for i in `find . -name "*.txt"`
> do
> mv $i ${i%.txt}.my
> done

Answer / asit pal

foreach x (`ls *.txt')
set y = `echo $x | cut -d . -f 1`
mv y y.my
done

Answer / prav gir

#!/bin/sh
for filename in *$1*
do
echo "$filename"
mv -f "$filename" `echo $filename|sed "s/$1/$2/"`
done
run script like
$>scrpt1 .txt .my

Answer / geichel

#!/bin/bash

for x in $(find $1 -name '*.txt' -type f )
do
OUT=$(echo $x | sed -e "s/\.txt$/.my/")
mv $x $OUT
done


exit 0;

Answer / venugopal adep

for file in `ls *.txt`; do new_file=`echo $file | sed
's/txt/my/g'`; mv $file $new_file; done

Answer / indu sharma

find . -name "*.txt" -exec ls {} \; | xargs -n1 -I{} sh -c 'mv "{}" `echo "{}"|basename "{}" .txt`.my'

Answer / sushanta

for i in *
do
p=`basename $i c`
q=$p "txt"
mv $i $q
done

Answer / veera

rename replacing-text replaced-test list-of-files
ex: rename .txt .my *.txt

Answer / aravind s

basename is the appropriate command to cut the unwanted
string from a filename

for example
$basename unix.txt txt #txt stripped off
unix.
-----------------------
for your problem the solution is

for i in `find . -name '*.txt'`|xargs ls; do
leftname=`basename $i txt`
mv $i ${leftname}doc
done
-----------------------

basename isn't a shell bulletin, but an external command.
The reason why we deal with it here is that it's most
effective when used with the for loop.

Ref: Unix Concepts & Applications - Sumitabha Das

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