int i; i=2; i++; if(i=4) { printf(i=4); }

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int i;
i=2;
i++;
if(i=4)
{
printf(i=4);
}
else
{
printf(i=3);
}
output of the program ?

Question Posted / guest

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int i; i=2; i++; if(i=4) { printf(i=4); } else { ..

Answer / sukant

The syntax for the if statement is also not correct..
The conditional assignment includes two == rather than a single =...
so,, the if statement wont consider that as a conditional statement and come out of it..
And, it will give an error in the printf(i=3); as the syntax is not apt.

Is This Answer Correct ?

0 Yes

0 No

int i; i=2; i++; if(i=4) { printf(i=4); } else { ..

Answer / khaja

output is 3

Is This Answer Correct ?

1 Yes

2 No

int i; i=2; i++; if(i=4) { printf(i=4); } else { ..

Answer / fwfwgq

It will give segmentation fault in linux

Is This Answer Correct ?

6 Yes

8 No

int i; i=2; i++; if(i=4) { printf(i=4); } else { ..

Answer / gowtham

answer is three

Is This Answer Correct ?

1 Yes

6 No

int i; i=2; i++; if(i=4) { printf(i=4); } else { ..

Answer / fazlur

the output will b 4.

Is This Answer Correct ?

6 Yes

18 No

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