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There are five thieves, each loot a bakery one after the
other such that the first one takes 1/2 of the total no.
of the breads plus 1/2 of a bread. Similarly 2nd, 3rd,4th
and 5th also did the same. After the fifth one no. of
breads remained are 3. Initially how many breads were there?
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Answer Posted / shailesh
guyz its better to go bottom to top in this prob
After 5th man 3 bread remained implies twice no. of (breads
minus half) available b4 him
there are (3-0.5) x 2 = 5 breads available before him
for 4th man
(5-0.5)x2=9
for 3rd man
(9-0.5)x2=17
for 2nd man
(17-0.5)x2=33
for 1st man
(33-0.5)x2=65
dats total 65 breads available
| Is This Answer Correct ? | 5 Yes | 8 No |
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