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If a person walks at 4/5th of his usual spee he reaches
40min late. If he walks athis usual speed how much time does
he travels.

Answers were Sorted based on User's Feedback

If a person walks at 4/5th of his usual spee he reaches 40min late. If he walks athis usual speed h..

let x=speed
t=time taken when speed is x so...
xt=4/5x(t+40)
t=160 minutes
2 hr 40 minutes

 Is This Answer Correct ? 78 Yes 3 No

If a person walks at 4/5th of his usual spee he reaches 40min late. If he walks athis usual speed h..

160 min or 2hr 40 min

 Is This Answer Correct ? 38 Yes 4 No

If a person walks at 4/5th of his usual spee he reaches 40min late. If he walks athis usual speed h..

do like this

(5/4) x - x = 40 min

1/4 x = 40 min

so x=160 min. hope u understand

 Is This Answer Correct ? 41 Yes 17 No

If a person walks at 4/5th of his usual spee he reaches 40min late. If he walks athis usual speed h..

in both cases person cover the same distance
hence
let t min time taken to cover the distance with actual speed x
hence
xt=4/5x(t+40)
=160 min
=2 hr and 40 min

 Is This Answer Correct ? 13 Yes 2 No

If a person walks at 4/5th of his usual spee he reaches 40min late. If he walks athis usual speed h..

given the person was late by 40mins when he walks at 4/5 of his normal speed

5*40min=200mins

he was late by 40mins so subtract it..

200-40=160mins

 Is This Answer Correct ? 9 Yes 2 No

If a person walks at 4/5th of his usual spee he reaches 40min late. If he walks athis usual speed h..

5x/4-x=40
x/4=40
x=160min

 Is This Answer Correct ? 6 Yes 0 No

If a person walks at 4/5th of his usual spee he reaches 40min late. If he walks athis usual speed h..

 Is This Answer Correct ? 8 Yes 10 No

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