there is a matrix N x N .Its elements consist of either
value =1 or value=0.
If there is a any zero in the row, then the output matrix
should have all zeroes in that row.
If there is a single zero in any column then that column
should have all zeroes n the output matrix.
write the function to perform these operations.
i want a solution in c/c++ language
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Answer / Manish Mishra
```cn#include <stdio.h>nnvoid printZeroRows(int matrix[][10], int size)n{n for (int i = 0; i < size; ++i)n {n int zeroCount = 0;n for (int j = 0; j < size; ++j)n {n if (matrix[i][j] == 0) ++zeroCount;n }n if (!zeroCount){n for (int k = 0; k < size; ++k)n matrix[i][k] = 0;n }n }n}nnvoid printZeroColumns(int matrix[][10], int size)n{n for (int i = 0; i < size; ++i)n {n int zeroCount = 0, zeroRow = -1;n for (int j = 0; j < size; ++j)n {n if (matrix[j][i] == 0)n {n if (!zeroCount)n {n zeroCount++;n zeroRow = j;n }n else matrix[zeroRow][j] = 0;n }n }n }n}nnint main()n{n int matrix[][10] = {n {1, 0, 1, 1},n {1, 1, 1, 0},n {1, 1, 1, 1},n {0, 1, 1, 1}n };n int size = sizeof(matrix) / sizeof(matrix[0]);n printZeroRows(matrix, size);n printZeroColumns(matrix, size);n for (int i = 0; i < size; ++i)n {n for (int j = 0; j < size; ++j)n {n printf("%d", matrix[i][j]);n if (j != size - 1) printf(" ");n }n printf("n");n }n return 0;n}n```
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