Answer / sudha chinnappa

I somehow feel that the code can be made more efficient. I
will leave this job to someone else


#include<iostream>
#include<conio.h> //for getch
using namespace std; //for cout

int main()
{
int arr[100];

cout << "Enter the No. of integers\n";
cin >> n ;

cout << "enter the numbers\n";
for(i=0; i<n; i++)
cin >> arr[i];

//Sort the numbers
for(i=0;i<n;i++)
{
for(j=i+1;j<n;j++)
{
if( arr[i] > arr[j] )
{
arr[j] = arr[i] + arr[j];
arr[i] = arr[j] - arr[i];
arr[j] = arr[j] - arr[i];
}
}
}

struct node
{
int num;
int frq;
node *nxt;
};

struct node *first = NULL, *temp, *temp1,*temp2;

i=0;
while(i<n)
{
temp = new node;
j=1;
while(arr[i] == arr[i+1])
{j++; i++;}

temp->num = arr[i];
temp->frq = j;
temp->nxt = NULL;

if (first == NULL)
first = temp;
else
{
temp1 = first;
while(temp1->nxt != NULL)
temp1 = temp1->nxt;

temp1->nxt = temp;
}
i++;
}

temp1 = first;
int large = first->frq;

temp1 = first;
temp2 = first->nxt;
while(temp1->nxt != NULL)
{
if(temp1->frq < temp2->frq)
large =temp2->frq;
temp1 = temp1->nxt;
temp2 = temp2->nxt;
}

cout << "\nHighest frequency numbers:\n\n";
cout << "Number Frequency\n";
temp1 = first;
while(temp1 != NULL)
{
if(temp1->frq == large)
cout << temp1->num << " "<< temp1->frq
<< endl;
temp1 = temp1->nxt;
}
}

Answer / paras malik

//I strongly feel that this signature is of java instead of
c++ with wrong signature name because function name
according to java conventions should start with small letter.

import java.util.HashMap;
import java.util.Set;

class A{



public static void main(String [] a){


int array[]={1,1,2,1,2,3,4,5,2,3,1};

array = GetFrequency(array);


for(int i =0;i<array.length;i++){

System.out.println(array[i] + "\n");

}

}



public static int[] GetFrequency(int [] array){

HashMap<Integer ,Integer > map = new HashMap<Integer,Integer>();



for(int i =0;i<array.length;i++){


if(map.get(array[i])==null) map.put(array[i],1);
else{
int k = map.get(array[i]);
map.put(array[i],k+1);

}

}

int a[] = new int[map.size()];

Set<Integer> set= map.keySet();
int i =0;
for(int s : set)
a[i++]=map.get(s);
return a;




}

}

Answer / rob lange

// I added a size input because I don't know how it would
// work without it. I also don't know what you're going
// to do without the returned size information, but whatever.
int* FindMax( int * list, int size )
{
// Check bad input conditions
if ( size == 0 )
return NULL;
else if ( size == 1 )
return list;

// Turn int pointer list into vector
int* curr = list;
std::vector< int > vList;
while ( size != 0 )
{
vList.push_back( *curr );
curr++;
size--;
}

// Sort
sort( vList.begin(), vList.end() );
vList.push_back( 0 ); // dummy tail node

// Find most frequent number
std::vector<int>::iterator i = vList.begin();
int curMaxLength = 0;
int tmpLength = 0;
std::vector<int> MostFreqNums;
while ( i+1 != vList.end() )
{
if ( *i == *(i+1) )
tmpLength++;
else
{
if ( tmpLength > curMaxLength )
{
MostFreqNums.clear();
MostFreqNums.push_back( *i );
curMaxLength = tmpLength;
}
else if ( tmpLength == curMaxLength )
{
MostFreqNums.push_back( *i );
}
tmpLength = 0;
}
++i;
}

// Convert vector list to int pointer array
int * ret = new int[ MostFreqNums.size() ];
i = MostFreqNums.begin();
for( int j = 0; i != MostFreqNums.end(); ++i, ++j )
{
ret[j] = *i;
}

return ret;
}

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0 Answers  

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Implement a command console for changing settings on a particular object. The command console should allow you to enter a string and will return the response (very similar to a terminal session). The commands are as follows: SET propertyname=newvalue will change the target object’s member named “propertyname” to have a value equal to “newvalue”. If the input value is incompatible (i.e. an int being set to a string), print out an appropriate error message. GET propertyname will print out the current value of the target object’s member named “propertyname”. GET * will print out a list of all target object members and their current values. The system should be extensible for future commands and should accept an arbitrary object, such that another developer could insert another object into the system and rely on the command console to get and set the properties correctly.

0 Answers   ABC, Guidance Software,

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write a program to perform generic sort in arrays?

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Subsets Write an algorithm that prints out all the subsets of 3 elements of a set of n elements. The elements of the set are stored in a list that is the input to the algorithm. (Since it is a set, you may assume all elements in the list are distinct.)

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Write a C/C++ program that connects to a MySQL server and displays the global TIMEZONE.

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Wrie a function which returns the most frequent number in a list of integers. Handle the case of more than one number which meets this criterion. public static int[] GetFrequency(int[] list)

3 Answers   Nagarro,

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Write a program using one dimensional array that accept five values from the keyboard. Then it should also accept a number to search. This number is to be searched if it among the five input values. If it is found, display the message “Search number is found!” otherwise, display “Search is lost”. Example: Enter 5 numbers: 10 15 20 7 8 Enter number to search: 7 Search number is found!

2 Answers   College School Exams Tests,

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What output does this program generate as shown? Why? class A { A() { cout << "A::A()" << endl; } ~A() { cout << "A::~A()" << endl; throw "A::exception"; } }; class B { B() { cout << "B::B()" << endl; throw "B::exception"; } ~B() { cout << "B::~B()"; } }; int main(int, char**) { try { cout << "Entering try...catch block" << endl; A objectA; B objectB; cout << "Exiting try...catch block" << endl; } catch (char* ex) { cout << ex << endl; } return 0; }

0 Answers  

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can we declare an object of a class in another class?(assume both class as public classes)

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Here's the programm code: int magic(int a, int b) { return b == 0 ? a : magic(b, a % b); } int main() { int a, b; scanf("%d%d", &a, &b); printf("%d\n", magic(a, b)); return 0; } on input stream we have integers 4, 45 What's the output integer? How many times will be initiated "magic" function?

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Teta-Omeg-Big-Oh Show that f(n) = n2 + 3n3 is ;(n3).

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