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Write a program using two-dimensional arrays that determines the highest and lowest of the 12 input values. Example: Enter 12 numbers: 13 15 20 13 35 40 16 18 20 18 20 14 highest: 40 lowest: 13

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A research student is given a singly-linked list. Each node of the list has a color, which is either “Black” or “White”. He must find if there are more black nodes than white nodes, or vice versa. His advisor gives him 5,000Rs to buy a computer to do the work. He goes to the computer store and finds a slightly defective computer which costs a mere 3,000Rs. This computer has the small problem of not being able to do arithmetic. This means that he cannot use a counter to count the nodes in the list to determine the majority color. The computer is otherwise fully functional. He has the evil idea that he could buy the defective computer and somehow use it to do his work, so that he can use the rest of the money on enjoyment. Show how he can accomplish this amazing task. Write code for an algorithm called ‘findMajorityColor’ which takes a singly-linked list, L, with n nodes and returns the majority color among nodes of L. This algorithm should have the same asymptotic running time as counting the nodes (O(n)). Note: No arithmetic is allowed.

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What will be the output- for(i=1;i<=3;i++) { printf("%d",i); continue; i++; }

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Complexity T(n) What is the time complexity T(n) of the following portions of code? For simplicity, you may assume that n is a power of 2. That is, n = 2k for some positive integer k. a) ? for (i = 1; i <= n; i++) { j = n; cout << i << ? ? j << ? ? << endl; } b) ? for (i = 0; i <= n; i += 2) { j = n; cout << i << ? ? j << ? ? << endl; } c) ? for (i = n; i >= 1; i = i/2) { j = n; cout << i << ? ? j << ? ? << endl; } d) for (i = 1; i <= n; i++) { j = n; while (j >= 0) { cout << i << ? ? j << ? ? << endl; j = j - 2; } }

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Definition of priority queue was given. We have to implement the priority queue using array of pointers with the priorities given in the range 1..n. The array could be accessed using the variable top. The list corresponding to the array elements contains the items having the priority as the array index. Adding an item would require changing the value of top if it has higher priority than top. Extracting an item would require deleting the first element from the corresponding queue. The following class was given: class PriorityQueue { int *Data[100]; int top; public: void put(int item, int priority); // inserts the item with the given priority. int get(int priority); // extract the element with the given priority. int count(); // returns the total elements in the priority queue. int isEmpty(); // check whether the priority queue is empty or not. }; We had to implement all these class functions.

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