Answer / sudha

#include<iostream>
#include<conio.h>
using namespace std;

int main()
{
string p[] =
{ "","","Twenty","Thirty","Fourty","Fifty","Sixty","Seventy","Eighty","Ninety" };
string o[] = { "","one", "two", "three", "four",
"five", "six", "seven", "eight", "nine" };

cout << "\n\nEnter a number between 20 to 99\n";
cin >> n;

i=n/10;
j=n%10;

cout << p[i] <<" " << o[j] << endl;

getch();
return(0);
}

Answer / vinay tiwari

#include<iostream.h>
#include<conio.h>
void main()
{
char a[9][10]=
{"one","two","three","four","five","six","seven","eight","ni
ne"};
char b[8][10]=
{"twenty","thirty","fourty","fifty","sixty","seventy","eight
y","ninety"};
int num,rem;
clrscr();
cout<<"enter number "<<"\n";
cin>>num;
rem=num%10;
num=num/10;
if(rem==0)
cout<<b[num-2]<<"\n";
else
cout<<b[num-2]<<" "<<a[rem-1];
getch();
}

Answer / pavan mustyala

#include<iostream>
using namespace std;

void main()
{
char *arr1[9]=
{"one","two","three","four","five","six","seven","eight","ni
ne"};
char *arr2[8]=
{"twenty","thirty","fourty","fifty","sixty","seventy","eight
y","ninety"};
int num;

cout << "Enter A Number:"<< endl;
cin >> num;

cout << arr2[(num / 10) - 2];

if((num % 10) != 0)
cout << " " << arr1[(num % 10) -1];
}

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